help factoring!! the problem is -16x2 + 60x + 16 then i factored the GCF of -4 and got -4(4x^2 - 15x - 4) but i can't seem to find nmbers that multiply to -4 and add to -15. am i right? or is multiply to 15 and add to 4? i need to find the zeros.
@math&ing001
@jim_thompson5910
multiply to be -16 and add up to be -15 is what you mean?
yea, i need to split the middle term
well what is -16(1) and -16+1 equal to?
original: -16x2 + 60x + 16 my gess after factoring GCF: -4(4x^2 - 15x - 4)
no, is -15 and -4
no...You are to find two factors of a*c that have product ac and sum b.
you need to find two number that multiply to be -16 and add up to be -15
ohh.....
thanks, i was in the wrong path lol
not entirely you were able to factor out that -4 from the start :)
lol true, well thank you!!
let me know if you have trouble
okay i get: -4(4x+1)(x-4) correct me if im wrong, im supposed to find the zeros... 4, -1/4, and 4 ?
@myininaya
looks great! :)
and the zeros...why do you have three of them
because -4 is factored out the parenthesis and i equaled to it zero
one is just a repetition but the x=4 only occurs once so you have the zeros are x=-1/4 or x=4
-4 can never be 0
4x+1 can be zero x-4 can be zero but -4 can never be zero
oh okay i see
i still think you did pretty well so i will give you a medal for your hard and good work
one more, correct me if im wrong, since the leading is negative, the parabola is going to open.... down?
thanks
very good
just making sure the info was frozen in my head, had to take this exam a few days ago so needed a refresher
|dw:1411170803194:dw| it has two x-intercepts x=4 and x=-1/4 as the graph shows and it is open down because the number in front of the x^2 is neg
i see
yea the zeros are x-intercepts
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