Question

Solve by completing the square. Look below

Answer 1

does it really matter how you solve it?

Answer 2

you want to multiply by 3 first to start with \[x^2+\frac{3}{2}x-3=0\] if you want to complete the square
otherwise, i would multiply by 6 instead and use the quadratic formula

Answer 3

you pick

Answer 4

multiply by 6..

Answer 5

then you would start with
\[2x^2+3x-6=0\]

Answer 6

use
\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=2,b=3,c=-6\]

Answer 7

Okay. :) thank youuu. i know already.

Answer 8

you get
\[\frac{-3\pm\sqrt{3^2-4\times 2\times (-6)}}{2\times 2}\]

Answer 9

yw

Answer 10

:)