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whats the circumference of the circle?
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@phi
\[C = \Pi D\]
That may not help too much, I looked at the picture after..
r^2 would go in place of the 50 so the radius is 7.07... or 7. and since diameter is 2xr, the diameter would be 14. but thats not up there
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they want you to notice the formula they gave you matches \[ (x - x_0)^2 + (y-y_0)^2 = r^2 \] that is the standard equation of a circle with a center at \( (x_0,y_0) \) and radius r if you match that with your problem you match \[ r^2 = 50 \] and , if you take the square root, \[ r = \sqrt{50}= \sqrt{2\cdot 5\cdot 5} = 5 \sqrt{2} \] That is a lot of stuff to know... But if you did know it, you would then say \[ C= 2 \pi \ r \]
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