Question

hello
could someone help me on this problem about a parallelogram
i need to find a side of the parallelogram

Answer 1

that is the area of the entire parallelogram...what i really need is the perimeter, but i guess i need to find the side first

Answer 2

There's information missing. Not sure what at this point.

Answer 3

But it's possible to construct many different parallelograms with those lengths but have the side L vary

Answer 4

i understand...but maybe with the data of the area...

Answer 5

does it give any info about the angles?

Answer 6

no...i will post the original problem.....

Answer 7

i already did the part a)

Answer 8

what is the length of ED

Answer 9

yes we can find that distance using the pytagora's theorem give me a second

Answer 10

the length ED is 8

Answer 11

what is the area of triangle AED

Answer 12

(1/2)8*6
it is 24

Answer 13

Triangle Area = 1/2 (6*8) = 24

Answer 14

so the area of trapezium ABCE is ????

Answer 15

i don't know...i m thinking

Answer 16

area of trapezium ABCE = (area of triangle AED) + (area of parallelogram ABCD)

Answer 17

since there are no gaps or overlaps

Answer 18

yes

Answer 19

i understand

Answer 20

what is that area?

Answer 21

24+30
= 54

Answer 22

now let

x = AB = CD (opposite sides in a parallelogram are congruent)

Answer 23

we must use this formula
\[A=(B+b)/2 *h\]

Answer 24

correct

Answer 25

is h =6 ?

Answer 26

so

A = (B+b)/2*h

54 = 6*(8+x+x)/2

I'm letting

B = 8+x which is the length of EC
b = x
h = 6
A = 54

Answer 27

b = x is the length of AB

Answer 28

i understand @jim_thompson5910

Answer 29

tangent Angle EDA = 6/10 = .6
arc tan (.6) = 30.964 degrees
angle DCB = 30.964 degrees

sin (30.964) = 3/DC
0.5145 = 3/DC
DC = 3/0.5145
DC = 5.8309

Answer 30

DC isn't 5.8309

Answer 31

i apprciate your help...i wish i could pay for this answer...

Answer 32

what is the value of x?

Answer 33

25

Answer 34

no

Answer 35

that is not correct

Answer 36

that is algebra...u did the important part

Answer 37

i will leave...thanks

Answer 38

sorry it is not correct...

Answer 39

54 = 6*(8+x+x)/2

54 = 6*(8+2x)/2

54*2 = 6*(8+2x)

108 = 6*(8+2x)

108 = 48 + 12x

108 - 48 = 12x

60 = 12x

12x = 60

x = 60/12

x = 5

Answer 40

So AB = 5 and CD = 5

Answer 41

i m sorry...yes that was not correct

Answer 42

that's ok

Answer 43

Using sine instead of tangent
sine Angle EDA = 6/10 = .6
arc sin (.6) = 36.87 degrees
angle DCB = 36.87 degrees

sin (36.87) = 3/DC
0.6 = 3/DC
DC = 3/.6
DC = 5