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Mathematics 8 Online
OpenStudy (anonymous):

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OpenStudy (mertsj):

It is against the rules of OS to spam the site.

OpenStudy (mertsj):

If you need help, ask a proper question.

OpenStudy (anonymous):

A tugboat can pull a boat 24 mi downstream in 2 hr. Going upstream, the tugboat can pull the same boat in 16 mi in 2 hr. What is the speed of the boat in still water? What is the speed of the current? : How can you use the formula d=rt to help you solve this problem? :How are the tugboat's speeds when traveling upstream and downstream related to its speed in still water and the speed of the current?

OpenStudy (mertsj):

Let r = the speed of the boat in still water Let c = the speed of the current Then r+c = the downstream speed of the boat and r - c = the upstream speed of the boat.

OpenStudy (mertsj):

rt = d Here is the downstream equation: (r+c)(2)=24 Here is the upstream equation: (r-c)(2) = 16

OpenStudy (mertsj):

Distribute the 2 in each equation.

OpenStudy (mertsj):

If you are listening, then distribute the 2 in each equation.

OpenStudy (mertsj):

The idea of open study is to guide the student, not to do their homework for them.

OpenStudy (mertsj):

Yes, r = 10 (r+c)(2)=24 Replace r with 10 and find c

OpenStudy (mertsj):

(10+c)(2)=24 Divide both sides by 2 (10+c)=12 Subtract 10 from both sides c=2

OpenStudy (mertsj):

Or: (10+c)(2)=24 Distribute the 2 20 + 2c = 24 Subtract 20 from both sides 2c=4 Divide both sides by 2 c = 2

OpenStudy (mertsj):

The tugboat can go faster when traveling downstream. It can go its still water speed plus the speed of the current because the current is pushing the boat along. The tugboat goes slower when traveling upstream. It goes it still water speed minus the speed of the current because the current is holding it back.

OpenStudy (mertsj):

Exc ellent

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