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Convergent or divergent
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\[a_n=\frac{ n! }{ 2^n }\] @ganeshie8
you're talking about sequence right ?
Yup
just making sure :)
Just started this so trying to figure things out, don't remember what n! really means
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Or wait so if 4! = 4*3*2*1, would n be something similar as well, like n*(n-1)*(n-2)..sort of thing?
I'm not sure how to really set these things up, my notes don't have anything specific.
the sequence won't converge if if the ratio \(\large \dfrac{a_{n+1}}{a_n}\) as n becomes large is not 1, yes ?
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