Mathematics
8 Online
OpenStudy (anonymous):
Write the quadratic function in the form.
f(x)=-2x^2-8x-12
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OpenStudy (anonymous):
@liz_mustang @Librarian @triciaal @e.mccormick @Compassionate @milkacha @fateal
OpenStudy (anonymous):
@ganeshie8
OpenStudy (fateal):
like this???
OpenStudy (anonymous):
Write the quadratic function in the form
f(x)=a(x-h)^2+k
OpenStudy (anonymous):
use completing the square formula/steps
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OpenStudy (anonymous):
i don't know how to do that
OpenStudy (anonymous):
well first of all try to factor out something that goes evenly in the 3 terms
OpenStudy (anonymous):
oh i actually do!!! Thats pre cal stuff, complete the square!
OpenStudy (anonymous):
give it a try before we give you answer, have you guys done any examples in class?
OpenStudy (anonymous):
@liz_mustang can you help me? @juniro no i in online classes
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OpenStudy (anonymous):
ok first factor out -2 from the equation
OpenStudy (anonymous):
this is how product should look after factoring
OpenStudy (anonymous):
then you can complete square
OpenStudy (anonymous):
let me check if that correct
OpenStudy (anonymous):
thats not the answer yet, you need to complete the square after you factor out -2
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OpenStudy (anonymous):
this is example of how to complete the square
OpenStudy (triciaal):
the posted question is not clear.
OpenStudy (anonymous):
you would use (b/2)^2 b=the number next to the x variable
OpenStudy (anonymous):
Write the quadratic function in the form. <<<f(x)=a(x-h)^2+k
f(x)=-2x^2-8x-12
OpenStudy (anonymous):
does the eponent 2 are added to -8x
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OpenStudy (triciaal):
no
OpenStudy (anonymous):
use the distribution properties
OpenStudy (anonymous):
so where does the exponent goes ?
OpenStudy (triciaal):
standard a = -2 b = -8 and c = -12
h = -b/2a and k = c + h^2
OpenStudy (anonymous):
what did you get when you factor out -2?
and after use (b/2)^2?
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OpenStudy (anonymous):
what x? @triciaal
OpenStudy (triciaal):
correct
OpenStudy (triciaal):
@sunnycali what do you mean "what x ? "