Question

**Trying to get the hang of this** help?
Write the equation of the line that is perpendicular to the line y = x + 4 and passes through the point (-6, 3).

A. y = x - 1

B. y = x + 3

C. y = -x - 1

D. y = -x + 3

Answer 1

What is the slope of y = x + 4

Answer 2

1 ?

Answer 3

correct since y = x + 4 is the same as y = 1x + 4

it is in the form y = mx+b where m = 1, b = 4

Answer 4

1 = 1/1

flip the fraction and flip the sign to get -1/1 which is just -1

so the perpendicular slope is -1

Answer 5

we want this new line to pass through (-6,3) so x = -6 and y = 3


y = mx + b

y = -1*x + b

3 = -1*6 + b

3 = -6 + b

3+6 = b

9 = b

b = 9

Because m = -1 and b = 9, the final answer is y = -x + 9

Answer 6

oh sorry my bad

Answer 7

I made a typo

Answer 8

y = mx + b

y = -1*x + b

3 = -1*(-6) + b

3 = 6 + b

3 - 6 = b

-3 = b

b = -3

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m = -1 and b = -3 so the equation is y = -x - 3

Answer 9

that makes so much more sense Thank you!!

Answer 10

unfortunately I don't see y = -x - 3 listed, but that is definitely the answer

Answer 11

so you'll have to bring it up with your teacher

Answer 12

Gotcha !