5a^2+23a+12 factor this, show work, i dont know how to do this
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OpenStudy (shamim):
23=20+3
right?
OpenStudy (triciaal):
do you know how to complete the square or do you know the quadratic formula?
OpenStudy (shamim):
20*3=60
OpenStudy (anonymous):
quadratic formula
OpenStudy (shamim):
5a^2+20a+3a+12
right?
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OpenStudy (anonymous):
i guess, why did u do the 20a+3a?
OpenStudy (triciaal):
@shamin I think you should start at the beginning to show why use 20 and 3
OpenStudy (triciaal):
see
OpenStudy (triciaal):
@shamim
OpenStudy (shamim):
20a+3a=23a
right?
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OpenStudy (anonymous):
i got -16.2 and -29.5 from using the quadratic formula
OpenStudy (shamim):
20a*3a=60a^2
OpenStudy (shamim):
nd 5a^2*12=60a^2
OpenStudy (triciaal):
@splatter6 @shamim is going through how to factor follow along for a minute @shamim please go through all the steps
OpenStudy (anonymous):
ok
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OpenStudy (shamim):
understood?
OpenStudy (anonymous):
no, i dont understand y u have a 60
OpenStudy (shamim):
60a^2=60a^2
right?
OpenStudy (triciaal):
@shamim please wait
@splatter6
OpenStudy (shamim):
need to show u a drawing
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OpenStudy (shamim):
bt i m now frm an android phone. so not possible to draw
OpenStudy (shamim):
sorry
OpenStudy (anonymous):
it's fine, i'll just ask my teacher
OpenStudy (shamim):
which grade u r
OpenStudy (anonymous):
im 11th
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OpenStudy (shamim):
r u frm usa?
OpenStudy (anonymous):
yeah
OpenStudy (shamim):
ok
OpenStudy (anonymous):
y
OpenStudy (shamim):
do u know middle term for factorisation?
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OpenStudy (anonymous):
no
OpenStudy (triciaal):
when you have a quadratic in the form ax^2 + bx + c to factor
find the product a*c and then the factors of that with the combination such that the sum will be the coefficient of x namely b
for this problem a = 5 b = 23 an d c = 12
so 5*12 = 60
what are the factors of 60 that when you add them the sum is 23
factors of 60 eg 6 and 10 , 15 and 4, 5 and 12 and the one used 20 and 3
now you have 5x^2 + 20x + 3x + 12 = 0
5x( x + 4) + 3( x + 4) = 0
@shamim will continue