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Okay so my question is. g(t)= (3t-5)^2+4t-1 Find g(a) And g(a+2). I am totally and utterly confused and would appreciate if someone could definitely explain this to me!
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Any ideas at all?
None in the slightest. I would understand if it said G(1) or something because I could plug that in. Do I just plug in a for x?
plug in a for t; there is no x.
I meant in for t, haha sorry!
Wouldn't it just be (3a-5)^2+4a-1 then?
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