Question

Does this limit exist, if so how would I solve it,
lim x->3 (1/x)((1/(x+3)^2)-(1/9))

Answer 1

Is that this:\[\lim_{x \rightarrow 3}(\frac{ 1 }{ x })(\frac{ 1 }{ (x+3)^{2} }-\frac{ 1 }{ 9 })\]

Answer 2

Yes

Answer 3

That's it exactly?

Answer 4

Yep

Answer 5

This can be solved by direct substitution of 3 in for x. There is no vertical asymptote created when you insert a 3. Try plugging in 3 for x. I did and got an answer of -1/36

Answer 6

Okay thats what I had but I thought that would be wrong, mind if I ask another question?