will reward medal for help. Indicate in standard form the equation of the line passing through the given points. A(4, 1), B(5, 2) I cant seem to nail this problem down. is this the right formula to solve it? (its an example) https://cornerstonetx.ignitiaschools.com/media/g_geo_2013/9/l9hg85.gif
first we find the slope using the slope formula slope(m) = (y2 - y1) / (x2 - x1) (4,1)....x1 = 4 and y1 = 1 (5,2)...x2 = 5 and y2 = 2 now we sub to find the slope slope(m) = (2 - 1) / (5 - 4) can you finish and find the slope....then we can continue
y-1= 1/1 (x-4) am i on the right track. i have no idea
ok...your using point slope formula....thats fine, we can use that or we can just use slope intercept formula, which is y = mx + b....how do you wish to continue ?
the simple easy way.
y = mx + b ....I usually just use this formula unless specifically asked to use point slope formula. y = mx + b slope(m) = 1/1, or you can just put 1 you can use either of your points...(4,1)....x = 4 and y = 1 now we sub...we are looking for b, the y intercept, since we already know the slope y = mx + b 1 = 1(4) + b 1 = 4 + b 1 - 4 = b -3 = b so our equation in slope intercept form is : y = 1x - 3, or you can just put y = x - 3 do you understand so far ? Any questions ? Let me know, if not, we can continue
i think i got it
that is slope intercept form, but we need it in standard form : Ax + By = C we have : y = x - 3 ----subtract x from both sides -x + y = -3 --- multiply everything by -1 to make x positive x - y = 3 --- standard form
any questions ?
im still confused
with what part ?
talk to me and let me help you
do you understand how to find the slope ?
do you understand how to turn an equation from slope intercept to standard ?
so our equation in slope intercept form is : y = 1x - 3, or you can just put y = x - 3 how did you get that
we found that our slope(m) was 1. slope intercept form is : y = mx + b we already know that slope (m) = 1 now we use either of our points....(4,1)....x = 4 and y = 1 now we sub our info into y = mx + b to find b, the y intercept y = mx + b 1 = 1(4) + b 1 = 4 + b 1 - 4 = b -3 = b now all you have to do is sub in your slope(m) and you y intercept(b) y = 1x - 3...or you can just put y = x - 3 did that help any ??
oh, yes, now i see
even if you used point slope formula : y - y1 = m(x - x1) slope(m) = 1 (4,1)...x1 = 4 and y1 = 1 y - 1 = 1(x - 4) --- distribute through the parenthesis y - 1 = x - 4 --- add 1 to both sides y = x - 4 + 1 y = x - 3....same thing
to turn it to standard form Ax + By = C y = x - 3 --- subtract x from both sides -x + y = -3 -- you cannot have a negative x, so multiply everything by -1 -x(-1) + y(-1) = -3(-1) x - y = 3 --- standard form
remember, a neg times a neg is a positive, and a pos times a neg is a neg
so you cant use point formula to get the standard form?
and even thought the x and y do not have a number in front of them, it is understood to be 1. yes...you can use point slope...because you will arrive at the same answer...because you are turning point slope to slope intercept and then to standard.
I just prefer to leave out the point slope and just do slope intercept....it just skips a step that is not necessarily needed
thanks!
sure thing :)
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