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Mathematics 10 Online
OpenStudy (anonymous):

14. Express f(x) = |x| as a piecewise function. a bit confused. I understand you set parameters in piece wise so. How do I express this? x>0 then x is positive if x<0 then x is positive?

OpenStudy (freckles):

what do you mean by x<0 then x>0?

OpenStudy (freckles):

x<0 does not imply x>0

OpenStudy (anonymous):

Yeah I know it doesn't imply it, that's why I was confused.

OpenStudy (freckles):

Let's look at an example |5|=5 <-- the 5 inside was positive |-5|=-(-5) <--the -5 inside was negative

OpenStudy (freckles):

So if x is positive then what can you say |x| equals?

OpenStudy (anonymous):

I couldn't think of something that showed f(x) = |x|

OpenStudy (anonymous):

It equals a positive number

OpenStudy (freckles):

x is a positive number

OpenStudy (anonymous):

Just as if it's negative it equals a positive number

OpenStudy (freckles):

so can |x|=x if x>0

OpenStudy (freckles):

just like |5|=5 because 5>0

OpenStudy (anonymous):

Yes I believe so

OpenStudy (anonymous):

Yes that makes sense

OpenStudy (freckles):

|-5|=-(-5) look at this

OpenStudy (freckles):

the number inside is negative in order to get a positive out of it we need to multiply inside number by -1

OpenStudy (freckles):

so if x<0 then |x|=?

OpenStudy (anonymous):

-1(-x)?

OpenStudy (anonymous):

Or just x?

OpenStudy (freckles):

well remember x is negative so -1(-x) is actually going to be negative

OpenStudy (freckles):

|-5|=-(-5) where -5<0 replace -5 with x

OpenStudy (anonymous):

Ah wait so it's |-x|=-(-x) where -x< 0

OpenStudy (freckles):

if i wanted to replace -5 with x wouldn't it be |x|=-x when x<0

OpenStudy (anonymous):

OHHHH

OpenStudy (anonymous):

Wow that just clicked in my head

OpenStudy (freckles):

yeah and if we graphed |x| it looks like |dw:1411365237885:dw|

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