Question

write an equation of a line that goes through point (4,-5) and is parallel to line y=2x+8.

Answer 1

y − y1 = 2(x − x1)
slope y=mx+b
here the slope is 2
y-(-5)=2(x-4)

Answer 2

so y+5=2x-4???

Answer 3

nopes y+5=2x-8

Answer 4

y=2x-8-5
y=2x-13

Answer 5

oooh, my bad, i forgot to distribute the 2 with the 4.

Answer 6

so would y=2x-13 be the answer??

Answer 7

yes...

Answer 8

alright, thank you!! can you help me with one more?

Answer 9

yw..sure

Answer 10

write an equation of the line in point-slope form, that passes through the given point and has the given slope.
point: (-2,15), (9, -18)

point: (8, -8); slope 3

Answer 11

they have those two set of numbers.

Answer 12

so u need 3 equations ryt

Answer 13

two. one for (-2, 15), 9,-18
and one for (8, -8) slope 3

Answer 14

y-15=-18-15/9-(-2) (x-(-2))

Answer 15

wpuld i distribute the 9 into all numbers?

Answer 16

y-15=-33/11(x+2)
y-15=-3(x+2)
y-15=-3x+6
3x+y=21

Answer 17

ooooh, okay! i see.

Answer 18

would the one with the slope be y-8=3(x+8)?

Answer 19

y − y1 = 3(x − x1)
y-(-8)=3(x-8)

Answer 20

y+8=3x-8?

Answer 21

yes,combine like terms.

Answer 22

-3x+y=-16

Answer 23

alright, thank you soooo much!!!

Answer 24

np c: