Question

Differentiate (6x^2*y)+(3y^2*x)=-9 with respect to x

Answer 1

use product rule
\[(fg)' = f'g + fg'\]
and every time you differentiate a "y" term you must multiply by "dy/dx"

Answer 2

ok did you insert an image to show the product rule?

Answer 3

and can you use y prime instead?

Answer 4

no i used the "Equation" button feature below

Answer 5

ty ill use that to help others too

Answer 6

yeah dy/dx = y'
same thing just diff notation

Answer 7

one of the terms is (9yx*y prime) how did you get that

Answer 8

nevermind

Answer 9

i know it will take so much typing to wite it out

Answer 10

not sure where the 9xy*y' comes from ?

you should get:
\[(12xy +6x^2 y') + (6xy y'+3y^2) = 0\]

Answer 11

i differentiated it already and got an answer ty