The code to unlock a safety deposit box is three consecutive odd integers whose sum is 81. Find the integers.
ok if n is an odd number what is the very next odd number?
i just don't get this! :(
if n is odd, wouldn't the next integer, n+1, be even? So the next odd integer would be n+2, right?
can you explain?
@freckles
say we have 3 what is the next odd integer after 3?
do you know what odd integers are?
6, 9?
6 is even because it is an integer divisible by 2 9 is odd because it an integer not divisible by 2 the next odd integer after 3 is 5
ohhh right, i got confused
1,3,5,7,9,11,13,15,17,19,21,23,25,27,... are all odd integers 2,4,6,8,10,12,14,16,18,20,22,24,26,28,... are all even integers
notice odd numbers are every other number
just like even numbers are every other number
so if i say n is an odd integer the next odd integer would not be n+1, but it would be n+2
because n,n+1 is not every other number
just like 3,3+2 <--this is two consecutive odd integers
replace 3 with n n,n+2 <--this is two consecutive odd integers
so what would the next odd consecutive integer after the n+2?
i will make it multiple choice for you: Fill in the blank. Assuming n is odd, the next odd integer after n+2 is __________. A) n+1 B) n+3 C) n+4 D) n+5
think about it 3,5,7 are 3 consecutive odd integers if we write 5 and 7 in terms of 3 and some other number we have 3,3+2,3+4
i just dont get it!! :(
again replace that 3 with n
n,n+2,n+4,n+6,n+8,n+10 are all odd assuming n is odd n,n+2,n+4,n+6,n+8,n+10 are all even assuming n is even Anyways the question says we have the sum of 3 conseuctive odd integers add up to be 81 we just said n,n+2,n+4 are 3 consecutive odd integers so we know by what was given that we have (n)+(n+2)+(n+4)=81
So you need to solve n+n+2+n+4=81 for n
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