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Mathematics 16 Online
OpenStudy (anonymous):

The code to unlock a safety deposit box is three consecutive odd integers whose sum is 81. Find the integers.

OpenStudy (freckles):

ok if n is an odd number what is the very next odd number?

OpenStudy (anonymous):

i just don't get this! :(

OpenStudy (freckles):

if n is odd, wouldn't the next integer, n+1, be even? So the next odd integer would be n+2, right?

OpenStudy (anonymous):

can you explain?

OpenStudy (anonymous):

@freckles

OpenStudy (freckles):

say we have 3 what is the next odd integer after 3?

OpenStudy (freckles):

do you know what odd integers are?

OpenStudy (anonymous):

6, 9?

OpenStudy (freckles):

6 is even because it is an integer divisible by 2 9 is odd because it an integer not divisible by 2 the next odd integer after 3 is 5

OpenStudy (anonymous):

ohhh right, i got confused

OpenStudy (freckles):

1,3,5,7,9,11,13,15,17,19,21,23,25,27,... are all odd integers 2,4,6,8,10,12,14,16,18,20,22,24,26,28,... are all even integers

OpenStudy (freckles):

notice odd numbers are every other number

OpenStudy (freckles):

just like even numbers are every other number

OpenStudy (freckles):

so if i say n is an odd integer the next odd integer would not be n+1, but it would be n+2

OpenStudy (freckles):

because n,n+1 is not every other number

OpenStudy (freckles):

just like 3,3+2 <--this is two consecutive odd integers

OpenStudy (freckles):

replace 3 with n n,n+2 <--this is two consecutive odd integers

OpenStudy (freckles):

so what would the next odd consecutive integer after the n+2?

OpenStudy (freckles):

i will make it multiple choice for you: Fill in the blank. Assuming n is odd, the next odd integer after n+2 is __________. A) n+1 B) n+3 C) n+4 D) n+5

OpenStudy (freckles):

think about it 3,5,7 are 3 consecutive odd integers if we write 5 and 7 in terms of 3 and some other number we have 3,3+2,3+4

OpenStudy (anonymous):

i just dont get it!! :(

OpenStudy (freckles):

again replace that 3 with n

OpenStudy (freckles):

n,n+2,n+4,n+6,n+8,n+10 are all odd assuming n is odd n,n+2,n+4,n+6,n+8,n+10 are all even assuming n is even Anyways the question says we have the sum of 3 conseuctive odd integers add up to be 81 we just said n,n+2,n+4 are 3 consecutive odd integers so we know by what was given that we have (n)+(n+2)+(n+4)=81

OpenStudy (freckles):

So you need to solve n+n+2+n+4=81 for n

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