Question

In a 2D rigid rotor the eigenfunctions are given the normalization of the wavefunction. Is it more likely to find a particle in the m=0 or m=1 state in a small region around phi=pi.

Answer 1

can you give us the form of the wavefunctions ?
the probability density to find the rotor in a particular orientation will be given by the modulus squared of the wavefunction for each state.

Answer 2

so thats what its asking :(

Answer 3

It's not so bad : )
To go from the wavefunction to the probability density, you need the modulus squared of the wavefunction.

Just in case you're not sure, you calculate the mod squared of the wavefunction by multiplying it by its complex conjugate.

Unless I am missing something, it seems to me that the mod squared of your wavefunctions is just 1/2pi in both cases, so the likelihood of the rotor being in a neighbourhood of phi=pi is the same for m=0 and m=1.