x^2+4x=10
x^2+4x-10
\[-b \pm \sqrt{b ^{2}-4ac}/2a\]
a=1,b=4 and c=-10 substitute the values
That's not what were doing.. it says "solve the equation by completing the square.
Oh, I think I can help you with this. :) Here are the steps... 1. Isolate the terms with x variables. (Already done for you in this case) 2. Complete the square. 3. Balance the equation. 4. Factor the perfect square trinomial. 5. Solve for x by taking the sqrt of both sides and isolating x. I'll guide you through the steps if you'd like...Let me know which one you are stuck on...:)
x^2+4x=10 x^2+4x+4=10+4 (x+2)^2=14 x+2=pm sqrt14 x=-2pm sqrt14
I need you to walk me through it
Looks like he did it for you. Lol any questions about what you see he did? :)
Where did the 4 come from?
take half of the x term then square it and add it to both the sides
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