Question

What is the vertical and horizontal asymptote of the equation:
3x^5+12x^4+6x^3-6x^2+3x-18/
x^5-4x^4+5x^3 -10x^2+4x+24

Answer 1

the horizontal asymptote is y = 3

its found by looking at the leading terms...

both degree 5

so look at the coefficients

3/1

so the horizontal is y =3

Answer 2

the verticals are harder, you need to find the values of x that make the denominator zero.

Answer 3

how do you do that?

Answer 4

what are the possible zeros of the equation?

Answer 5

here is an easy solution, graph them and then read them off...

as there only 3 vertical asymptotes there must be some multiplicity to the zeros of the denominator

to check, just graph the denominator as a function and look at the zeros.

hope it helps

Answer 6

i still don't understand how to find all the possible zero

Answer 7

@campbell_st