Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

(Help please) Given f(x) = , solve for f-1(3). 2 4 6 8

OpenStudy (stefrheart):

wait please rewrite it

OpenStudy (stefrheart):

the equation

OpenStudy (anonymous):

f(x)= 4x+1/3 solve for f- 1(3)

OpenStudy (anonymous):

this sorry

OpenStudy (stefrheart):

is it supposed to be x=3 right?

OpenStudy (anonymous):

yea

OpenStudy (stefrheart):

first you need to replace the x with the 3

OpenStudy (anonymous):

I'm really not sure what to do so do I multiply 4*3 first?

OpenStudy (stefrheart):

yes so that would equal..

OpenStudy (anonymous):

12

OpenStudy (anonymous):

then would i divide 12 by 3?

OpenStudy (stefrheart):

well isnt there a plus one?

OpenStudy (anonymous):

but don't you divide before adding?

OpenStudy (stefrheart):

true that is true but what are your choices?

OpenStudy (anonymous):

2 4 6 8

OpenStudy (stefrheart):

hm...

OpenStudy (stefrheart):

can you take a pic of the whole question? everything?

OpenStudy (anonymous):

yea hold on

OpenStudy (stefrheart):

thank you

OpenStudy (anonymous):

OpenStudy (anonymous):

sorry its so difficult to read

OpenStudy (stefrheart):

its okay i got 8

OpenStudy (stefrheart):

but i am not totally sure since it is \[f ^{-1}(3)\]

OpenStudy (anonymous):

ok thank you so much! I can understand simple equations but now that I'm in algebra 2 well.... anyways thank you.

OpenStudy (stefrheart):

yes but do you understand how i got 8? and welcome lol i took adv alg 2

OpenStudy (anonymous):

no, but it'd be really helpful if you could explain it a bit because I got 5 and that's not an answer.

OpenStudy (stefrheart):

oh man i totally just lost my work but this is an odd problem that could either end up as 5 or 13

OpenStudy (anonymous):

hmm it was actually 2 which I have no idea how it's 2, but thank you for the help.

OpenStudy (stefrheart):

oh sorry :) its a weird question but its math all questions are weird

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!