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F=P(1+j/m)^n HELP!!
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find j
is it \[F=P(1+\frac{ j }{ m })^{n} \] or \[F = P (\frac{ 1+j }{ m })^{n}\]
@shinalcantara the 2nd
\[F=P(\frac{ 1+j }{ m })^{n}\] divide both sides by P \[\frac{ F }{ P } = \frac{ P }{ P }(\frac{ 1+j }{ m })^{n}\] \[\frac{ F }{ P } = (\frac{ 1+j }{ m })^{n}\] get the nth root of each side \[\sqrt[n]{\frac{ F }{ P }} = \frac{ 1+j }{ m }\] cross multiply m to the left side of the equation \[\sqrt[n]{\frac{ F }{ P }} * m = 1+j\] subtract 1 to both sides \[\sqrt[n]{\frac{ F }{ P }} * m -1 = 1 + j -1\] \[\sqrt[n]{\frac{ F }{ P }} * m -1 = j \] or \[j = m * \sqrt[n]{\frac{ F }{ P }} -1\]
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