What is set builder notation?
what do you mean?
If you tell me what you mean I can help you :)
well like here is an example problem, I have no clue what to do with it :c
A shorthand used to write sets, often sets with an infinite number of elements. Note: The set {x : x > 0} is read aloud, "the set of all x such that x is greater than 0." It is read aloud exactly the same way when the colon : is replaced by the vertical line.
how would you start out with it?
@beccamarie603 that's correct I was about to say that LOL
haha
@DarkBlueChocobo read the link that @ganeshie8 gave you its VERY helpfull
well you have a wonderfull day and I hope you good luck on that test! bye for now :)
for that particular problem, first figure out what the domain is
Would this be an example of the problem at hand ganeshie?
yes, the denominator of a fraction can never be 0
yes exatly
\[\large \dfrac{3-x}{5x+1}\]
what @ganeshie8 said the demomator of a fraction can never be 0 or else you can't get your answer
Since the denominator equals 0 when x = -1/5, the domain includes everything except this : Domain = \(\large \{x | x \ne \frac{1}{5}\}\)
Alrights sorry if i have delay i keep looking at the link ganeshie gave and come back aha
erg this seems complex >.<
*** Domain = \(\large \{x | x \ne -\frac{1}{5}\}\)
read it as : "x such that x is not equal to -1/5"
like, if you don't like pineapples, you would order like below in a juiceshop : " fruit such that the fruit is not pineapple "
how did you find that though?
could you go through tthe steps
you do know how to find the domain of a rational function right ?
well i do not think so :c sadly
Is 3/0 a number?
no because the denominator cant be 0
wait is that like when you break down an equation ganeshie
do you mean, you want to set the denominator equal to 0 and solve x so that you find what exactly makes the denominator 0 ?
simply set the denominator equal to 0 and solve x that gives you exclude values for the domain whats the denominator in your rational function ?
5x+1=0 x=--1/5
why two negative signs -- ?
oh it was a miss type only ment one aha
:) so x = -1/5 is the evil value that makes your function go crazy so exclude it from the domain
are there any other values for x that make your function undefined ?
Alright so that is why it would be be b
yes your funciton is OKays for all other values of x, the only exclude value is -1/5
Alright so that makes sense but for the next one it changes. Do you just set the denominator to 0 and check to see if it is not equal to 3/5?-
factor "-1" from the numerator and see what you get
well im confused because there isnt -1 there >.<
well, we can write ` a-b ` as ` -(b-a) `
just an algebra game
ohh so -(5x-3)?
are you rearranging denominator like that ?
\[\large \dfrac{5x-3}{3-5x} = \dfrac{5x-3}{-1(5x-3)}\]
you can cancel 5x-3 top and bottom, assuming 5x-3 is never 0
\[\large \dfrac{5x-3}{3-5x} = \dfrac{5x-3}{-1(5x-3)} = -1 ;~~5x-3 \ne 0\]
wouldnt this just switch the signs?
Erg *facepalm* i forgot you said denominator not numerator T-T
no, i said both to confuse you ;P
you could do that to either of them, it doesnt matter
so what i see is that you factored -1 into the denominator and canceled out 5x-3 then got =1 for your answer?
-1*
thats right !
alright thank you for taking the time to explain this to me haha
so then this would be false
its true ! facepalm moment for meh lol
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the statement in your question says exactly what we concluded just now go thru it again :)
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what makes you so happy @edmodo :)
i am going to pre order dragonball xenoverse today
i read the reviews of the game and its going to be great
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are you going to get xenoverse too
im not much into gaming unless you call pacman a game! but dragonball sounds cool, hope you have lots of fun :)
ok i like pacman too he is on the newest supr smash bros on wii u or 3ds
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