A cab charges $1.50 for the first mile and $0.50 for each additional mile. Write and solve an inequality to determine how many miles Sharon can travel if she has $25 to spend. $0.50 + $1.50x ≤ $25; x ≤ 16 miles $0.50 + $1.50x ≥ $25; x ≥ 16 miles $1.50 + $0.50x ≤ $25; x ≤ 47 miles $1.50 + $0.50x ≥ $25; x ≥ 47miles
First, write a linear expression for the cost of the cab ride. This cost has a fixed component ($25) and a variable component ($0.50 per additional mile) times the number of additional miles).
I would have to say choice C
why
C
$1.50 + $0.50x ≤ $25; x ≤ 47 miles
1.50 is the fee, which will be your y-intercept, it's what you start with. 0.50 will become 0.50x, where x = additional miles. And 0.50 is your slope. And it also says how far she can travel with $25. So ≤ 25
We have: $1.50 + $0.50x and So ≤ 25.
let x be the no of miles.for each xtra mile its 0.50 =0.50x 1.50+0.50x is less then or equal to $25
thanks guys wich one the best respose
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