Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

In the figure below, EC || AB. Find the length of EA. A. 5 B. 7.5 C. 8.5 D. 10

OpenStudy (anonymous):

OpenStudy (freckles):

you be able to use the fact that those are similar triangles

OpenStudy (freckles):

i'm talking triangle DEC and triangle DAB

OpenStudy (freckles):

this should allow you to find side DE

OpenStudy (freckles):

and then you can do 15-DE to find AE

OpenStudy (anonymous):

I understand what you're saying, I just can't get it together though :/ like I can't get it idk why

OpenStudy (freckles):

\[\frac{DE}{15}=\frac{8}{12}\]

OpenStudy (freckles):

Solve that for DE

OpenStudy (anonymous):

omg so 10

OpenStudy (anonymous):

thanks so much @freckles :)

OpenStudy (freckles):

Well DE is 10

OpenStudy (freckles):

What is AE?

OpenStudy (freckles):

@lianacarolina are you still there?

OpenStudy (anonymous):

yes i'm here okay so i need to find ae

OpenStudy (freckles):

Ok look at your picture and remember we just found DE and were asked to find AE You are given the length of AD which is 15

OpenStudy (freckles):

You should see that the length of DE plus the length of AE is the length of AD

OpenStudy (freckles):

basically DE+AE=AD And and AD=15 so we have DE+AE=15 and we just found DE=10 10+AE=15

OpenStudy (anonymous):

So then AE is 5

OpenStudy (freckles):

yes

OpenStudy (anonymous):

i see, wow thank you. would you mind helping with 2 more?

OpenStudy (freckles):

i might be able to help you with one more food is on the way

OpenStudy (anonymous):

okay i will make this fast then In the figure below, BD bisects ∠ABC. Find the length of DC.

OpenStudy (anonymous):

OpenStudy (anonymous):

there's 1.2, 2.4, 3.6 & 4.8 as answers

OpenStudy (freckles):

|dw:1411598270027:dw| again we have similar triangles try to set up the ratios that are equal

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!