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Differentiate F(x)=3x^2 - 2cosx
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6x + 2sinx. do you need the working?
yes please
3x^2 becomes 6x cause you bring down the power and subtract the original by 1 (it's a bit weird typing it out i hope you understand). so essentially it's like (2)3^(2-1) which gives you 6^1... for the second one, when you differentiate cosf(x) you get -f'(x)sinf(x), so f'(x) of -2cosx will give you -2(-1)sinx = +2sinx and then you combine everything n you get 6 + 2sinx.
can you visualise it? typing math out is hard hahaha
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