Question

Twenty years ago a small town in Texas had a population of 10,000. The population has increased 8% each year since then. What is the growth factor that would be used to solve this problem?
a.
The growth factor would be 8
b.
The growth factor would be 0.08
c.
The growth factor would be 1.08
d.
The growth factor would be 0.92

Answer 1

percent means per 100
8% = 8/100 = 0.08

Answer 2

can someone please help me!

Answer 3

thank you so much!

Answer 4

to get the population it would be the original PLUS the increase
to get the new population can use original * 1.08

Answer 5

Find the missing value for the exponential function represented by the table below.
X. -2 Y. 21
-1 14.7
0 10.29
1
2 5.0421



a.
9.213
c.
7.203
b.
8.756
d.
-7.203

Answer 6

can you explain it to me @triciaal

Answer 7

multiple choice I would use C
I don't like this question the factor should just be by how much it has increased 0.08 as stated but to find the new population use 1.08 original plus increase

Answer 8

can you explain the one above pls

Answer 9

do you have the formula?

Answer 10

is it y = e^x?

Answer 11

no all i have is what i sent you. i need to find the missing value for X

Answer 12

can you use logs?

Answer 13

no it doesnt have a formula

Answer 14

@jim_thompson5910 @satellite73 can you please help

Answer 15

@amistre64 , @acxbox22 can you please help

Answer 16

@besqueda9 sorry I don't know. tried to get you some help

Answer 17

thank you so much anyway. youve been helpful

Answer 18

@bibby

Answer 19

hint: notice how

sqrt(21*10.29) = 14.7

the 21 and 10.29 are values in the y column. The 14.7 is between 21 and 10.29

Answer 20

you will have to develop an exponential function using a system of equations

y = a b^(x-h) + k

Answer 21

not 'have to' but that would be my approach

Answer 22

@jim_thompson5910 , @amistre64 thank you