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Mathematics 20 Online
OpenStudy (anonymous):

can someone please explain the process of how to factor -5x+32x^3+4(10x^4-1)? Im just really lost on how to do this

OpenStudy (anonymous):

\[-5x+32x^3+4(10x^4-1)\]?

OpenStudy (anonymous):

yes, thats the problem

OpenStudy (anonymous):

yikes my guess is to multiply out first, and start with \[40x^4+32x^3-5x-4\] and then maybe try to find the zeros to factor it

OpenStudy (anonymous):

oh i see the gimmick

OpenStudy (anonymous):

this is the dreaded "factor by grouping" factor an \(8x^3\) out of the first two terms

OpenStudy (anonymous):

ohhh okay

OpenStudy (anonymous):

\[40x^4+32x^3-5x-4\\ 8x^3(5x+4)-5x-4\]

OpenStudy (anonymous):

then \[8x^3(5x-4)-1(5x+4)\]

OpenStudy (anonymous):

okay then is that my final answer?

OpenStudy (anonymous):

finally \[(8x^3-1)(5x-4)\]

OpenStudy (anonymous):

oh no hardly not done yet

OpenStudy (anonymous):

i made a typo the line \[8x^3(5x-4)-1(5x+4)\] should be \[8x^3(5x+4)-1(5x+4)\]

OpenStudy (anonymous):

oh :( so is it (2x-1)(4x^2+2x+1)(5x+4)

OpenStudy (anonymous):

yeah i think so

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

actually i am sure yw

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