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find the derivitive
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\[9^x+\frac{ 2 }{ x^5 }\]
second part should be easy for the first on you need to remember that \[\frac{d}{dx}[b^x]=b^x\ln(b)\] always
ok, so the first part is ln(9) 9^x?
yup
ok. is the second part \[-\frac{ 3 }{ x^6 }\]
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hhmm no
if it helps, write it as \[2x^{-5}\] then use the all mighty power rule
ok. then do you use nx^n-1 to get 2*-5x^-6?
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