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Mathematics 13 Online
OpenStudy (anonymous):

Limit question help anyone?

OpenStudy (anonymous):

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

I honestly don't know how to approach this myself.

OpenStudy (alekos):

fascinating limit problem let f(x)=y so we have y + 1/y = 2 (assume that lim x->0 is in front of each y) solving for y we get (y-1)^2 = 0 then we get y=1 so lim x->0 f(x) =1

OpenStudy (anonymous):

Okay let me do it out myself.

OpenStudy (alekos):

I am fairly sure that the limit rules still hold whilst carrying out this manipulation

OpenStudy (anonymous):

Yes it does. Nothing wrong with that. Let me just do it out myself to confirm.

OpenStudy (anonymous):

I solved it differently but I still get y=1.

OpenStudy (anonymous):

@alekos

OpenStudy (anonymous):

Wait I messed up.

OpenStudy (anonymous):

Yep got it.

OpenStudy (anonymous):

Thanks.

OpenStudy (alekos):

no problem, glad i could help

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