Ask your own question, for FREE!
Trigonometry 20 Online
OpenStudy (anonymous):

From a point A on level ground, the angles of elevation of the top,D,and bottom,B, of a flagpole situated on the top of a hill are measured as 47degrees and 54 min. and 39 degrees and 49 min. . Find the height of the hill if the height of the flagpole is 115.5ft.

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

i will get the angle B?

OpenStudy (anonymous):

how can i find the height of the hill?

OpenStudy (anonymous):

can i get first the angle B...then use trigonometric function?

OpenStudy (gorv):

yeah sum of angle of triangle is 180 and you have two angle so you can find the third

OpenStudy (anonymous):

i got 50 degrees 15 min. in angle B AND D= 42degrees 6 min

OpenStudy (anonymous):

how can i find the length of the hill?

OpenStudy (anonymous):

height*

OpenStudy (gorv):

|dw:1411639520171:dw|

OpenStudy (gorv):

first we are looking at top and from same position at bottom

OpenStudy (gorv):

|dw:1411639613526:dw|

OpenStudy (gorv):

BOA & DOA are right angle triangle

OpenStudy (anonymous):

so how can i get OB?

OpenStudy (gorv):

\[\tan \theta= \frac{ perpendicular }{ base }\]

OpenStudy (gorv):

tan (angle BOA)=OB/OA

OpenStudy (gorv):

tan(angle DAO)= OD/OA

OpenStudy (gorv):

tan (47 degree 54 min)=x/OA

OpenStudy (gorv):

tan(39degree 49 min)=(x-115.5)/OA

OpenStudy (gorv):

solve these 2 find value of OA and put it in Other

OpenStudy (anonymous):

what formula will i use ..you give me a damn many formulas hehe

OpenStudy (gorv):

for trianle DOA

OpenStudy (anonymous):

what formula?

OpenStudy (gorv):

tan (47 54')=x/ OA now tell me the value of OA

OpenStudy (anonymous):

i that OA or BA?

OpenStudy (gorv):

ok tell me first

OpenStudy (gorv):

in right angle triangle tan(theta)= ?????

OpenStudy (anonymous):

i dont know..because i dont know the value of x

OpenStudy (gorv):

tell me in term of x

OpenStudy (anonymous):

tan(47degrees54min.)=1.10672

OpenStudy (gorv):

take x as x and tell than??

OpenStudy (anonymous):

\[OA=\frac{ x }{ \tan (47degrees 54\min. }\]

OpenStudy (gorv):

yeah now from triangle BOA tan (theta)=???

OpenStudy (gorv):

OB=x-115.5

OpenStudy (anonymous):

how?

OpenStudy (gorv):

BOA is aright angle triangle

OpenStudy (gorv):

tan(39 degree 49 minute )=????

OpenStudy (anonymous):

0.8337

OpenStudy (gorv):

loll tan (theta)=??? in right angle triangle BOA

OpenStudy (anonymous):

can you just get to the point .. i dont know what is it please!!1

OpenStudy (gorv):

|dw:1411641369080:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!