From a point A on level ground, the angles of elevation of the top,D,and bottom,B, of a flagpole situated on the top of a hill are measured as 47degrees and 54 min. and 39 degrees and 49 min. . Find the height of the hill if the height of the flagpole is 115.5ft.
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OpenStudy (anonymous):
how?
OpenStudy (anonymous):
i will get the angle B?
OpenStudy (anonymous):
how can i find the height of the hill?
OpenStudy (anonymous):
can i get first the angle B...then use trigonometric function?
OpenStudy (gorv):
yeah sum of angle of triangle is 180
and you have two angle so you can find the third
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OpenStudy (anonymous):
i got 50 degrees 15 min. in angle B AND D= 42degrees 6 min
OpenStudy (anonymous):
how can i find the length of the hill?
OpenStudy (anonymous):
height*
OpenStudy (gorv):
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OpenStudy (gorv):
first we are looking at top and from same position at bottom
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OpenStudy (gorv):
|dw:1411639613526:dw|
OpenStudy (gorv):
BOA & DOA are right angle triangle
OpenStudy (anonymous):
so how can i get OB?
OpenStudy (gorv):
\[\tan \theta= \frac{ perpendicular }{ base }\]
OpenStudy (gorv):
tan (angle BOA)=OB/OA
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OpenStudy (gorv):
tan(angle DAO)= OD/OA
OpenStudy (gorv):
tan (47 degree 54 min)=x/OA
OpenStudy (gorv):
tan(39degree 49 min)=(x-115.5)/OA
OpenStudy (gorv):
solve these 2 find value of OA and put it in Other
OpenStudy (anonymous):
what formula will i use ..you give me a damn many formulas hehe
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OpenStudy (gorv):
for trianle DOA
OpenStudy (anonymous):
what formula?
OpenStudy (gorv):
tan (47 54')=x/ OA now tell me the value of OA
OpenStudy (anonymous):
i that OA or BA?
OpenStudy (gorv):
ok tell me first
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OpenStudy (gorv):
in right angle triangle
tan(theta)= ?????
OpenStudy (anonymous):
i dont know..because i dont know the value of x
OpenStudy (gorv):
tell me in term of x
OpenStudy (anonymous):
tan(47degrees54min.)=1.10672
OpenStudy (gorv):
take x as x and tell than??
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OpenStudy (anonymous):
\[OA=\frac{ x }{ \tan (47degrees 54\min. }\]
OpenStudy (gorv):
yeah now from triangle BOA
tan (theta)=???
OpenStudy (gorv):
OB=x-115.5
OpenStudy (anonymous):
how?
OpenStudy (gorv):
BOA is aright angle triangle
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OpenStudy (gorv):
tan(39 degree 49 minute )=????
OpenStudy (anonymous):
0.8337
OpenStudy (gorv):
loll
tan (theta)=???
in right angle triangle BOA
OpenStudy (anonymous):
can you just get to the point .. i dont know what is it please!!1