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Mathematics 16 Online
OpenStudy (anonymous):

Find the implied domain and range of y=cos(2arcsinx) can someone please check if im solving it correctly? Thanks

OpenStudy (anonymous):

u=2arcsinx -------> Range of arcsinx [-pi/2,pi/2] cos has restricted the domain: [0,pi]

OpenStudy (anonymous):

in the textbook it has the domain [0,1] and range [-1,1]. is it correct?

OpenStudy (anonymous):

can someone please correct me if im wrong but my answer is: domain [0,sqrt2/2] and range [0,1]

OpenStudy (anonymous):

@loser66

OpenStudy (loser66):

2arcsin x has domain [-1,1] and range [-pi,pi ] from cos , we need cos (-pi) = -1 and cos (pi) = -1 also. However, among [-pi,pi] we have the value of pi/2 which gives us cos (pi/2) = 0 so that the range of cos is [-1,0]

OpenStudy (loser66):

https://www.desmos.com/calculator/2djmpyhbrf

OpenStudy (anonymous):

Isn't the range from cos supposed to be [-1,1]

OpenStudy (loser66):

oh, yes, you are right. I am sorry.

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