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Find the implied domain and range of y=cos(2arcsinx) can someone please check if im solving it correctly? Thanks
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u=2arcsinx -------> Range of arcsinx [-pi/2,pi/2] cos has restricted the domain: [0,pi]
in the textbook it has the domain [0,1] and range [-1,1]. is it correct?
can someone please correct me if im wrong but my answer is: domain [0,sqrt2/2] and range [0,1]
@loser66
2arcsin x has domain [-1,1] and range [-pi,pi ] from cos , we need cos (-pi) = -1 and cos (pi) = -1 also. However, among [-pi,pi] we have the value of pi/2 which gives us cos (pi/2) = 0 so that the range of cos is [-1,0]
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Isn't the range from cos supposed to be [-1,1]
oh, yes, you are right. I am sorry.
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