Question

What is the equation of the lines that passes through the poins of (0,1) and (6,-2)

Answer 1

First you do need to find the slope of the line based on
m=(y2-y1)/(x2-x1)

so for these points: (0,3) and (2,0) --> (x1, y1) and (x2, y2)
x1=0
y1=3
x2=2
y2=0

m= (0-3)/(2-0) = -3/2

Then your formula will need to look like y=mx+b where b is your y-intercept (when x=0)
Due to have the x=0 point, you are pretty much done:

y=-3/2*x+3

If you do not have a (0,y) form, you can solve as follows:
Write out the formula with your slope value inserted:
y=-3/2*x+b

Choose one of your points on your line to solve for b. I choose (2,0):
0=-3/2*2+b
0=-3*1+b
3=b --> b=3

Answer 2

Ok so you have two points given, so first lets find the slope.
(0,1)(6,-2) is also (X1,Y1)(X2,Y2).