What is the equation in standard form of the line which passes through (6, 3) and has a slope of two thirds?

2x + 3y = 3

2x − 3y = 3

3x + 2y = 3

3x − 2y = 3
@DolphinDawg @thatgirlcaleigh

Question

What is the equation in standard form of the line which passes through (6, 3) and has a slope of two thirds? 

 2x + 3y = 3 

 2x − 3y = 3 

 3x + 2y = 3 

 3x − 2y = 3 
@DolphinDawg  @thatgirlcaleigh

anonymous · Answer

The point at which the line passes through is (6,3) i.e. x1 = 6 & y1 = 3, and it has a slope or gradient, m = 2/3. 
In order to get the line that passes through those points, you need to make use of the formula: y - y1 = m(x - x1), by substitution you'll have 
y - 3 = (2/3)(x - 6) 
3(y - 3) = 2(x - 6) 
3y - 9 = 2x - 12 
3y - 2x = - 12 + 9 
3y - 2x = - 3 
2x - 3y = 3 ...Ans. 
Option B is correct.