Find the sum of these 12 vectors in a wall clock A+B+C+...+L http://prntscr.com/4qaiyc
each vector is separated by 360/12 = 30 degrees
the vectors start at center of the circle
and end on circle
It will be 0.
Wow! how ?
What will you get when you add vector a and vector h?
hehe! that's some fast answer
I mean D and J
It will be 0. The same thing will happen with other pairs.
brilliant!!!!!
one more side question related to this
shall i ask it here or open a new thread?
Well, it's up to you. I like your avatar. :)
Suppose the 12 vectors start from 6:00 am at the bottom instead of (0,0) at the center. whats the sum of new 12 vectors ?
wow! i completely caught of guard and i was thinking about something else
@xapproachesinfinity Kind of tricky. What do you think about this question?
me too haha! i was trying euler formula
i mean for the first question... but you gave a nice cute solution xD
This question is not tricky anymore. x_x
yeah no opposite vectors to cancel ;-;
I think you can try adding H and J, G and K, etc.
nice :) x components eat each other out, and y components double ?
I don't think y will get double.
yeah the first was tricky! it drove think about other things! really when things simplify to zero and ones you appreciate the beauty of math hehe
<3 the second question seems to be having not so nice answer, i could try trig/exponents if there is easy way out
the vertical vector going thru center is of length : 2 units in y direction
F and jJsum to nC n some scalar??
F and J
adding F and L gets rid of x components right ?
no actually B and H give C the diagram is confusing lol
OMG! yess they do give C which is 2
i have created this diagram quickly... so please bear with me :) consider only th blue labels outer to the circle
the other way D + J also give C
Yes, I didn't think about that. Good job. @xapproachesinfinity
I'm sure this have cancellations as we go along
C+I = 2 D+J = 2 E+K = 2 F+L = 2 G+A = 2 H+B = 2
12 xD thank you both :)
good^_^ seems that was the way to think about it
Welcome
Yes there is always something tricky about the opposite letters.
I got another tricky question on vectors in cube, will post in a new thread :) need your help on that too... i gave up after trying for some time
let's see i have little time though! hehe
It's great to know you two.
pleasure is mine^_^
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