Fiber-optic cables are used widely for internet wiring, data transmission, and surgeries. When light passes through a fiber-optic cable, its intensity decreases with the increase in the length of the cable. If 1500 lumens of light enters the cable, the intensity of light decreases by 3.4% per meter of the cable.
Can anyone help me?
@ayoubEpst
help me
what's the question ?
Fiber-optic cables are used widely for internet wiring, data transmission, and surgeries. When light passes through a fiber-optic cable, its intensity decreases with the increase in the length of the cable. If 1500 lumens of light enters the cable, the intensity of light decreases by 3.4% per meter of the cable. Part A: Can this situation be represented by a linear function? Justify your answer. (2 points) Part B: Write a function f(x) to represent the intensity of light, in lumens, when it has passed through x meters of the cable. (4 points) Part C: Some scientists are trying to make a cable for which the intensity of light would decrease by 5 lumens per unit length of the cable. Can this situation be represented by a linear function? Justify your answer and write the appropriate function to represent this situation if 1500 lumens of light enter the cable. (4 points)
hlpe me with part c
@Brilliance help
y=intial intensity -5x
y=1500-5x
so what do I write for part c
would it be 1500= -5 not sure at all tho
f(x)=1500-5x
Can this situation be represented by a linear function?
yes
can u tell me why?
because it polynomial function of degree one
the taut of decreasing is constant
im not at polynomial yet.this is linear and exponential growth
and im confused bu taut.
@ayoubEpst r u still here?
yes
linear growth
I don't get what u mean by taut
what you know about linear function ?
I wouldn't be asking you if I know. I suck at math.
hello?
ok, but what do u mean by taut
@-StudyShark- can you help me?
taut is the degree of
so what do I submit for part c?
yes because a=constan=-5 f(x)= 1500-5x
is it good if I submit 1500 starting point and decreases by 5 each time so it's linear.
hello?
yes
ok thank you, I have one more question. Can you help me? ill make a new question and ill tag u in
okey ( but i'm tired ) si itry
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