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If n is a positive integer prove that when we divide n^2 by 5 we get that r=0,1 or 4
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In case you are wondering r would be the remainder in elementary divison
consider n = 5k, 5k+1, 5k+2, 5k+3, 5k+4
work the 5 cases separately
Right, oops.....I totally should have seen splitting it up that way and not the way I did....lol thanks
Will close when I fully solve
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np :) thats one way, there is another nice way if you're allowed to use congruences
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