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OpenStudy (anonymous):
medal and fan
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OpenStudy (anonymous):
Question?
OpenStudy (slinley):
Question??
OpenStudy (anonymous):
complete the standerd form of the equation y=10-5/2x
OpenStudy (anonymous):
_x+_y=20
OpenStudy (anonymous):
Wait y = 10-5?
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OpenStudy (anonymous):
and What is the x-intercept of the line with the equation 1/3x+y=-15(_,0)
OpenStudy (slinley):
y = 10^-5
OpenStudy (slinley):
wait :)
OpenStudy (slinley):
y = 1/3 0I thinkkkk
OpenStudy (anonymous):
but thats not what it asks
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OpenStudy (anonymous):
theres two seperate questions
OpenStudy (anonymous):
@sammixboo
OpenStudy (anonymous):
@aum
OpenStudy (slinley):
Can you give me a medal and fan me? I'll give you the same, Thanks!
OpenStudy (aum):
\[
y = 10 - \frac 52x \\
\text{Multiply by 2:} \\
2y = 20 - 5x \\
\text{Add 5x} \\
5x + 2y = 20 ~~~\text{ is the standard form.}
\]
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sammixboo (sammixboo):
Sorry for not responding! Do you still need help?
OpenStudy (anonymous):
on the second question
OpenStudy (aum):
\[
\frac 13x + y = -15 \\
\text{To find x-intercept, set y = 0 and solve for x.} \\
\]
OpenStudy (aum):
\[
\frac 13x + y = -15 \\
\text{put y = 0} \\
\frac 13x + 0 = -15 \\
\text{To solve for x, multiply by 3:} \\
x = -45 \\
\text{x-intercept: }~~(-45, 0) \\
\]
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