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Going over parametric equations...help?
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The path x = 2y = 3z = 6t is a _______ traveled with speed ____ How is this a line? I am just drawing a blank?
thats a line passing through origin divide by 6 to change it into symmetric form
\[\large \dfrac{x}{6} = \dfrac{y}{3} = \dfrac{z}{2} \]
\[\large \dfrac{x-0}{6} = \dfrac{y-0}{3} = \dfrac{z-0}{2} \]
it passes through (0,0,0) and the direction vector is (6,3,2)
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you may write it in parametric form as (0,0,0) + t(6,3,2)
Ahhh!!!! yeah completely drew a blank....not used to seeing x = y = z I'm used to seeing t = x + y - z.....etc... yeah that's the form! thank you much @ganeshie8 !
np :)
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