Question

Can someone help me understand how to convert g(x) = 2(x-6)^2 and f(x)=x^2 to g in terms of f using function notation? http://prntscr.com/4qmw8v

Answer 1

I feel like I'm over thinking this....

Answer 2

ok can you expand g(x)=2(x-6)^2
I'm asking you to write 2(x-6)^2 in standard form
this form ax^2+bx+c
and then I think it is asking you to replace x^2 with f(x)
but I'm not entirely sure what to do with x
just leave it or also write it in terms of f
,,,

what is that f(x^2) thing you wrote?

Answer 3

the thing with writing x in terms of f
is we will have actually two relations for g in terms of f

Answer 4

my question "what is that f(x^2) thing you wrote?" is referring to the screenshot you provided

Answer 5

So g(x) = 2x^2 -24x +72 and then substitute x^2 for f(x)?

Answer 6

and you can actually solve x^2=f(x) for just x by square rooting both sides
so you could replace x with \[\pm \sqrt{x}\]
this seems kinda weird to me
but yeah this is writing g in terms of f

Answer 7

perl you have something to add?

Answer 8

yes the question seems odd, maybe we can see the question before this one

Answer 9

i agree it seems weird to me too

Answer 10

if f(x) = x^2, then g(x) = 2*f(x) - 24 * sqrt(f(x)) +72

Answer 11

oops i mean to say you can replace x with \[\pm \sqrt{f(x)}\]
sorry that was a type-o above