Consider the parabola y = 5x + x^2
a) Find the slope of the tangent line to the parabola at the point (1, 4).
b) Find the equation of the tangent line of part (a)

Question

Consider the parabola y = 5x + x^2
 a) Find the slope of the tangent line to the parabola at the point (1, 4).
b) Find the equation of the tangent line of part (a)

anonymous · Answer

so the parabola is $$y = 5x + x ^{2}$$

loser66 · Answer

Where are you stuck?

anonymous · Answer

the slope of the tangent line would i use the slop formula?

loser66 · Answer

yes

anonymous · Answer

so $$y- y ^{1} = m(x-x ^{1^{}})$$

anonymous · Answer

and i would input the tangent line for y1 and x1

gorv · Answer

just differentiate y with respect to x

gorv · Answer

dy/dx=5+2x
at (1,4)
dy/dx=5+2*1=7

gorv · Answer

now you have slope and ponit it pass through

gorv · Answer

use y=mx+c
put point in equation
4=7*1+c
c=-3
so tangent
y=7x-3

aum · Answer

The formula you used is for finding slope of a straight line.  Here it is curve.  So you will have to find the derivative and then plug in x value to find the slope.

loser66 · Answer

@holls622  When you said "the slope of the tangent line would i use the slop formula?", I assumed you know how to find the "slop formula" meaning