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Mathematics 7 Online
OpenStudy (anonymous):

Is this a relation function? {(14,15)(5,7)(3,10)(11,1)(5,8)}

OpenStudy (tbnrfrags):

A relation is not a function if there are 2 "y" values for any given "x" value. So, if you have multiple "x"'s (first number in each ordered pair), then there is no function.

OpenStudy (tbnrfrags):

So, you go through each ordered pair, one by one. First ask if there are multiple "14". If yes, then no function. If not, go to the next ordered pair. Are there multiple 5's? If yes, no function. If not, then go to the third, etc

jagr2713 (jagr2713):

i dont think so b/c 5 repeats twice so NOT A FUNCTION

jagr2713 (jagr2713):

whenever a number repeats for the x its not a function

OpenStudy (tbnrfrags):

jagr you would be correct

jagr2713 (jagr2713):

You to

OpenStudy (anonymous):

No mam, because there are 2 different y values for one x value. (5,7) and (5,8)

OpenStudy (anonymous):

Thanks! So what would a relation function be??

jagr2713 (jagr2713):

@grray7 its really the x's

OpenStudy (tbnrfrags):

http://www.purplemath.com/modules/fcns.htm you may find this website helpful

jagr2713 (jagr2713):

a relation function would be {(14,15)(5,7)(3,10)(11,1)(7,8)}

jagr2713 (jagr2713):

none of the x's repeat

OpenStudy (tbnrfrags):

true story

OpenStudy (tbnrfrags):

im trying to get 50 smartcents xD

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