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Mathematics 19 Online
OpenStudy (anonymous):

Can someone explain to me how I do this? http://i60.tinypic.com/x6h9oi.png

OpenStudy (mathmale):

Let me ask you a few questions first. In these problems, what does "end behavior" mean? How does the graph of y=x^2 behave if you start with negative x and move to the right towards positive x?

OpenStudy (anonymous):

It increases right?

OpenStudy (mathmale):

No. Please draw the graph of y=x^2 and then try again to answer my 2nd question.|dw:1411864430298:dw|

OpenStudy (mathmale):

"increases" partially right, but you will see why "increases" is not the correct response if you're able to draw the graph of y=x^2 properly.

OpenStudy (anonymous):

|dw:1411864505413:dw| Something like that, hqar

OpenStudy (mathmale):

Good enough. Now, describe the behavior of the function as you go from x=-5 towards x=0. Next, describe the behavior as you from 0 to +5.

OpenStudy (anonymous):

Both increasing? -5 to 0 is increasing, right? and 0 to +5 is increasing.

OpenStudy (mathmale):

Hint: the function is increasing as soon as you pass x=0 going to the right. Try again.

OpenStudy (anonymous):

I'm lost, is -5 to 0 Decreasing?

OpenStudy (anonymous):

And 0 tp +5 increasing?

OpenStudy (anonymous):

@mathmale

OpenStudy (xapproachesinfinity):

let's reform things again as i approach 0 from the left |dw:1411871845707:dw|

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