Question

What is the equation of the line that passes through (-2, 2) and (1, -4)?


y = 2x - 2

y = -2x - 4

y = -2x - 2

y = 2x + 4

Answer 1

is it y = -2x - 2

Answer 2

slope formula:
\[m = \frac{ y2-y1 }{ x2-x1 }\]
\[m = \frac{ -4-2 }{ 1-(-2) }\]
solve for the slope first

Answer 3

-6/3= -2

Answer 4

we'll use again that same formula with slope as -2 and a point.
either (-2,2) or (1,-4)
in this case let me use (1,-4)
\[m = \frac{ y2-y1 }{ x2-x1 }\]
\[-2 = \frac{ y - (-4) }{ x-1 }\]
cross multiply
\[-2(x-1) = y+4\]
\[-2x + 2 = y + 4\]
\[y + 2x + 4 - 2 = 0\]
\[y + 2x + 2 = 0\]
or in slope intercept form:
\[y = -2x -2\]