Question

How would I find the cumulative distribution function (CDF) of the following:
f(x) = e^(-x^2/2a^2) * (x/a^2)
?

Answer 1

assuming f(x) as the density function,
CDF is :
\(\Large CDF = \int \limits_{-\infty }^x f(x)dx\)

Answer 2

to solve that integral,
please try substitution method
u = -x^2/2a^2

and let me know if you get stuck at any step :)

Answer 3

Thanks so much hartnn, that really helps. I'll hit you up if I hit another snag in this statistics homework I'm doing!

Answer 4

sure, welcome ^_^