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OpenStudy (anonymous):
OpenStudy (anonymous):
what assumptions are we making about cubes which aren't completely visible?
OpenStudy (anonymous):
that is, do we assume 11 cubes on first level?
OpenStudy (math&ing001):
You 16 cubes, each cube has 6 face. So the total faces would be 6*16. Simply count the visible ones and deduct them from the total number.
OpenStudy (anonymous):
6 sides per cube, with 16 cubes => 96 total faces.
24 faces visible => 72 invisible faces, right?
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OpenStudy (anonymous):
24 cubes?
OpenStudy (anonymous):
I understand now @pgpilot326 . Thank you (:
OpenStudy (anonymous):
great! you're welcome!
OpenStudy (mathstudent55):
Let's start with a simpler example.
Here are 6 cubes
How many hidden faces are there here?
|dw:1411923444578:dw|
OpenStudy (mathstudent55):
Hidden faces are not simply faces you don't see in the figure from the angle you are looking. Hidden faces are faces that you can't see from any angle.
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OpenStudy (mathstudent55):
@Calyssa00
What answer did you get to the original question?