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Mathematics 9 Online
OpenStudy (anonymous):

....

OpenStudy (anonymous):

OpenStudy (anonymous):

what assumptions are we making about cubes which aren't completely visible?

OpenStudy (anonymous):

that is, do we assume 11 cubes on first level?

OpenStudy (math&ing001):

You 16 cubes, each cube has 6 face. So the total faces would be 6*16. Simply count the visible ones and deduct them from the total number.

OpenStudy (anonymous):

6 sides per cube, with 16 cubes => 96 total faces. 24 faces visible => 72 invisible faces, right?

OpenStudy (anonymous):

24 cubes?

OpenStudy (anonymous):

I understand now @pgpilot326 . Thank you (:

OpenStudy (anonymous):

great! you're welcome!

OpenStudy (mathstudent55):

Let's start with a simpler example. Here are 6 cubes How many hidden faces are there here? |dw:1411923444578:dw|

OpenStudy (mathstudent55):

Hidden faces are not simply faces you don't see in the figure from the angle you are looking. Hidden faces are faces that you can't see from any angle.

OpenStudy (mathstudent55):

@Calyssa00 What answer did you get to the original question?

OpenStudy (mathstudent55):

Answer is 34.

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