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Find an equation of the tangent line to the curve y=4xsin(x) at the point (π/2,2π). Express your answer in the form y=mx+b. i know the derivative is 4sinx+4xcosx
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derivative at point \((\pi/2 , 2\pi) \) will give you the slope of tangent at that point
so plug in x = pi/2 in your derivative
yes but i got the wrong answer
what slope did u get ?
4
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thats correct y - 2pi = 4 (x - pi/2) you got this ? simplified ? what did u get ?
y=4(x-pi/2) +2pi
yep multiply 2 on both sides
or distribute 4 to (x-pi/2)
do u get the final answer as y =4x ?
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Pi/2 then
yes i got the answer
cool, any more doubts ?
nope
thank you
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welcome ^_^
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