how do you solve X^3-4x+3=0
by inspection, 1 is a root
will you be able to solve if you know one of the roots ?
here its very easy to find, SUM of co-efficients = 0 hence x=1 must be the root
synthetic division and quadratic formula are your best friends here
agreed, synthetic or long division i'd go for synthetic
yes synthetic division it's the best method to solve this
for ANY polynomial, its easy to determine whether x=1 or x=-1 is one of the solution if sum of ALL co-efficients = 0 , then x= 1 is a root if sum of co-efficients of even exponents of x = sum of co-efficient of odd exponents of x, then x=-1 is the root
I know how to solve quadratic eq...i just dont get how did u know 1 was a root?? O.o did u just guess? O.o
no guess this is acceptable reason if sum of ALL co-efficients = 0 , then x= 1 is a root
+1 and -1 are the first things to guess and check
if you still don't want to use that you can use rational root theorem
a cubic has a direct formula but its very messy and very very hard to solve it analytically. so you should always try +1, -1 and every other rational root thats predicted by rational root theorem
woooow...i didnt know that O.o Thanks a lot Hartnn :D
if you know it, you will need to check for just these values +1,-1,+3,-3
also descartes rule of signs makes ur life a bit easy by eliminating few of the roots (doesn't matter for current problem as 3 is a prime)
you're welcome ^_^ you'll get a quadratic after synthetic division also, you can have a look here http://openstudy.com/study#/updates/504335bee4b000724d4620b4
for \(ax^3+bx^2+cx+d =0\) a,b,c,d are the co-efficients if a+b+c+d = 0, then x= 1 is the root example : x^3 - 4x+6x-3 what are the co-efficients ?
1 -4 and 3 = 0 thankssss :")
1, -4 , 6 , -3 add them, you get 0
similarly, let me give you an example for x=-1 x^3 - 3x^2 +3x - 1 what are co -efficients of x^3 and x ?? add them what are co -efficients of x^2 and constant ?? add them
1-3+3-1 = 0 so whenever it goes equal to 0, it means the root is 1? what about the other thing that x-1 is the factor?
ok, i messed up with the example for this case too, x=1 is one of the solution, yes because sum of co-efficients is 0 now if 'a' is a root, (x-a) is a factor!
no prob lol :P i understood the main part :) it's a factor so i can factorize the main equation?
yes i mean you can use that for synthetic division you'll use x=1
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and where did those 3 come from? O.o ://
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