Please guys help me!! Even if u know only one point !
Given the equation kx+3y−2=0
(a) Find the value k such that the point (−1, 5) belongs to the line
(b) Find the value of p such the previous line is perpendicular to 3x − py + 7 = 0.
(c) Find the points of intersection.

Question

Please guys help me!! Even if u know only one point !
Given the equation kx+3y−2=0
(a) Find the value k such that the point (−1, 5) belongs to the line
(b) Find the value of p such the previous line is perpendicular to 3x − py + 7 = 0. 
(c) Find the points of intersection.

jhonyy9 · Answer

a) (-1,5) mean that for x= -1 will get y= -5 so than 

   kx+3y=2
    3y=2-kx
     y=(2-kx)/3

 -5 = (2-k(-1))/3
 -5 = (2+k)/3
-15= 2+k
-17 = k

hope these will help you