write an equation in standard form using only intergers for the line descrived.
The line perpendicular to x-3y=7 and containing (-2,5)
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OpenStudy (anonymous):
do you know how to find the slope of the line x-3y=7 ?
OpenStudy (anonymous):
1/3
OpenStudy (anonymous):
perpendicular lines have negative reciprocal slope with the slope of the original line. So first thing you have to do is find the slope of the given line.
OpenStudy (anonymous):
1/3
OpenStudy (anonymous):
right. then get the negative reciprocal of 1/3. which will be..?
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OpenStudy (anonymous):
-3
OpenStudy (anonymous):
great :)
so so far you have the slope of the perpendicular line which is m=-3
\((y-y_1)= m(x-x_1)\) are you familiar with this?
OpenStudy (anonymous):
or y=mx+b
OpenStudy (anonymous):
yeah same thing. but \((y-y_1)= m(x-x_1)\) is easier when doing the standard form.
where \((x_1 , y_1)\) is your given point.
substitute all the values given
\(m=-3, x_1=-2, y_1=5\)
OpenStudy (anonymous):
3x+y=-1
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OpenStudy (anonymous):
awesome! you don't need any help lol. you can do it :)