Question

medalsss!!!
Evaluate x={-4,-3,-2,5,3}
1. x= -4, y=
2. x= -3, y=
3. x= -2.5, y=
4. x=3, y=

Answer 1

can yall help me

Answer 2

@shinebrightlikeadimon

Answer 3

Idek~ x.x

Answer 4

frlsss @arabpride

Answer 5

wuuuuuuuuuuuut iz this?! cx

Answer 6

its like equations

Answer 7

I don't remember doing/learning this

Answer 8

ok

Answer 9

i get it's equations lmfaoo but wut kinda math bruh?!

Answer 10

Algebra lol

Answer 11

@skullpatrol

Answer 12

Ma algebra never looked like that x.x

Answer 13

Evaluate the function x = {-4, -3, -2.5, 3}.
x = -4, y = x = -3, y = x = -2.5, y = x = 3, y =

Answer 14

thas what it looks like

Answer 15

Not enough info, I believe. We don't know the relationship between x and y.

Answer 16

ok hold on plzz

Answer 17

2. Given f(x) = x2 – 3x + 1, find the value of the function for {-4, -3, -2.5, 3} by graphing the function. @geerky42

Answer 18

x^2-3x+1

Answer 19

thas the function

Answer 20

this the question Evaluate the function x = {-4, -3, -2.5, 3}. x = -4, y = x = -3, y = x = -2.5, y = x = 3, y =

Answer 21

Ask your teacher to explain it for you, sometimes they end up given you the answer and explaining it to you incase you bump in a similar question in the future

Answer 22

yea but its sunday. i cant tlk to a teacher

Answer 23

To find the value of y at x = -4, you just plug -4 into x then solve for y or f(x).

\(f(\mathbf{\color{red}x}) = \mathbf{\color{red}x}^2-3\mathbf{\color{red}x}+1\)
\(f(\mathbf{\color{red}{-4}}) = (\mathbf{\color{red}{-4}})^2-3(\mathbf{\color{red}{-4}})+1 = \cdots ~?\)

Answer 24

ok

Answer 25

Do the same for x=-3, x=-2.5 and so on.

Answer 26

so what was the answer for the first one

Answer 27

Can you solve \(f(-4)\)?

Just solve \((-4)^2-3(-4)+1\). Can you do that?

Answer 28

yes i can

Answer 29

So what is it?

Answer 30

let me see

Answer 31

29 is the answer right

Answer 32

@geerky42